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Question: Answered & Verified by Expert
P is a point on the conic a2x2+b2y2=a2a2+b2-y2 and S is a focus of that conic. M is the foot of the perpendicular from P on to a directrix of that conic nearer to S. If PM=KSP, then K=
MathematicsEllipseTS EAMCETTS EAMCET 2021 (04 Aug Shift 2)
Options:
  • A ba2+b2
  • B a2+b2b
  • C aa2+b2
  • D a2+b2a
Solution:
2689 Upvotes Verified Answer
The correct answer is: a2+b2b

Given, equation of conic

a2x2+b2y2=a2a2+b2-y2

a2x2+b2y2+a2y2=a2a2+b2

a2x2a2a2+b2+y2b2+a2a2a2+b2=1

x2a2+b2+y2a2=1  i

Equation i represents an ellipse whose eccentricity is given by 

e=1-a2a2+b2=ba2+b2

Also, we know that in a conic,

Distance of a moving point P from focus S=e×Perpendicular distance of a point P from directrixPM

SP=ePM

PM=1eSP=KSP

K=1e=a2+b2b

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