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$\sim(p \vee q) \vee(\sim p \wedge q)$ is logically equivalent to
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Verified Answer
The correct answer is:
$\sim p$
$\sim(p \vee q) \vee(\sim p \vee q))$
$\equiv(\sim p \wedge \sim q) \vee(\sim p \wedge q)$
$\equiv \sim p \wedge(\sim q \vee q) \equiv \sim p$
$\equiv(\sim p \wedge \sim q) \vee(\sim p \wedge q)$
$\equiv \sim p \wedge(\sim q \vee q) \equiv \sim p$
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