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Question: Answered & Verified by Expert
Paragraph:
$$
\mathrm{RCONH}_2 \text { is converted into } \mathrm{RNH}_2 \text { by means of Hofmann bromamide degradation. }
$$

In this reaction, $R \mathrm{CONHBr}$ is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann degradation reaction is an intramolecular reaction.Question:
Which is the rate determining step in Hofmann bromamide degradation?
ChemistryAminesJEE AdvancedJEE Advanced 2006
Options:
  • A
    Formation of (i)
  • B
    Formation of (ii)
  • C
    Formation of (iii)
  • D
    Formation of (iv)
Solution:
1468 Upvotes Verified Answer
The correct answer is:
Formation of (iv)
The rate determining step is probably elimination of $\mathrm{Br}^{-}$to form isocyanate because it is slower step of given conversion.

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