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$$
\mathrm{RCONH}_2 \text { is converted into } \mathrm{RNH}_2 \text { by means of Hofmann bromamide degradation. }
$$
In this reaction, $R \mathrm{CONHBr}$ is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann degradation reaction is an intramolecular reaction.Question:
Which is the rate determining step in Hofmann bromamide degradation?
Options:
$$
\mathrm{RCONH}_2 \text { is converted into } \mathrm{RNH}_2 \text { by means of Hofmann bromamide degradation. }
$$

In this reaction, $R \mathrm{CONHBr}$ is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann degradation reaction is an intramolecular reaction.Question:
Which is the rate determining step in Hofmann bromamide degradation?
Solution:
1468 Upvotes
Verified Answer
The correct answer is:
Formation of (iv)
Formation of (iv)
The rate determining step is probably elimination of $\mathrm{Br}^{-}$to form isocyanate because it is slower step of given conversion.
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