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Question: Answered & Verified by Expert
Particles are released from rest at A and slide down the smooth surface of height h to a conveyor B. The correct angular velocity ω of the conveyor pulley of radius r to prevent any sliding on the belt as the particles transfer to the conveyor is

PhysicsLaws of MotionNEET
Options:
  • A 2gh
  • B 2ghr
  • C 2ghr
  • D 2gh2r2
Solution:
2947 Upvotes Verified Answer
The correct answer is: 2ghr
First of all, we have to calculate the velocity of particles at the point B.

Loss in P.E. = gain in K.E.

Or mgh=12mv2

v= 2gh

To prevent sliding, v=rω

ω=vr=2ghr

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