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Question: Answered & Verified by Expert
PCl 5 vapour decomposes on heating according to the reaction:
PCl 5 g PCl 3 g + Cl 2 g
The density of a sample of a partially dissociated PCl 5 at 1.0 atm and 500K was found 4.8g/L. Calculate the degree of dissociation and Δ G   for the reaction at 500K.
(Given:  R=0.082 LatmK 1 mol 1 ,  R=8.314 JK 1 mol 1 , lnx=2.303 log 10 x ) If your answer is K, mark 2K as answer after rounding off to nearest integer.
ChemistryChemical EquilibriumJEE Main
Solution:
1656 Upvotes Verified Answer
The correct answer is: 47
M avg = ρ RT P = 4.8 × 0.0 8 2 × 5 0 0 1 = 1 9 6.8
PCl 5 g PCl 3 g + Cl 2 g 1 - α α α Total moles = 1 + α
M avg = M PCl 5 1 + α = 1 9 6.8 = 2 0 8.5 1 + α
  α = 0.0 6
K P = α 2 1 α 2 P= 0.06 2 1 0.06 2 =3.6× 10 3
Δ G = - RT  ln  K
         = - 8.3 1 4 × 5 0 0 × 2.303  log  3.6 × 1 0 - 3
         =23.4kJ

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