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Question: Answered & Verified by Expert
Pent-1-ene reacts with diborane to form $\mathrm{X}$. X on oxidation using $\mathrm{H}_2 \mathrm{O}_2$ in the presence of aqueous $\mathrm{NaOH}$ gives $\mathrm{Y}$. Compound $\mathrm{Y}$ is
ChemistryHydrocarbonsAP EAMCETAP EAMCET 2018 (24 Apr Shift 2)
Options:
  • A $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_3$
  • B $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{OH}$
  • C $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_2 \mathrm{CH}_3$
  • D $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{C}(\mathrm{OH})\left(\mathrm{CH}_3\right) \mathrm{CH}_3$
Solution:
1921 Upvotes Verified Answer
The correct answer is: $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{OH}$
No solution. Refer to answer key.

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