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$\mathrm{PhCH}_2 \mathrm{Cl} \stackrel{\text { aq. NaCN }}{\longrightarrow} ? \stackrel{\text { Catalytic hydrogenation }}{\longrightarrow}$
The final product $(U)$ is :
Options:
The final product $(U)$ is :
Solution:
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Verified Answer
The correct answer is:
$\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NH}_2$
$$
\begin{aligned}
& \mathrm{PhCH}_2 \mathrm{Cl} \stackrel{\text { aq. } \mathrm{NaCN}}{\longrightarrow} \mathrm{PhCH}_2 \mathrm{CN} \\
& \stackrel{\text { Cat. hydrogenation }}{\stackrel{\mathrm{H}_2, \mathrm{Pd}}{\longrightarrow}} \mathrm{PhCH}_2 \mathrm{CH}_2 \mathrm{NH}_2
\end{aligned}
$$
(U)
\begin{aligned}
& \mathrm{PhCH}_2 \mathrm{Cl} \stackrel{\text { aq. } \mathrm{NaCN}}{\longrightarrow} \mathrm{PhCH}_2 \mathrm{CN} \\
& \stackrel{\text { Cat. hydrogenation }}{\stackrel{\mathrm{H}_2, \mathrm{Pd}}{\longrightarrow}} \mathrm{PhCH}_2 \mathrm{CH}_2 \mathrm{NH}_2
\end{aligned}
$$
(U)
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