Photons of energy 1 eV and 2.5 eV successively illuminated a metal whose work function is 0.5 eV. The ratio of maximum speeds of emitted electron is

Question

Photons of energy 1 eV and 2.5 eV successively illuminated a metal whose work function is 0.5 eV. The ratio of maximum speeds of emitted electron is, 1 : 3, 1 : 2, 3 : 1, 2 : 1

MARKS App · Accepted Answer

Energy of photon E = ϕ + 1 2 m v 2 V max ⁡ = 2 E - ϕ m So putting values V max ⁡ 1 V m a x 2 = 1 - 0.5 2.5 - 0.5 V max ⁡ 1 V max ⁡ 2 = 1 2

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