Search any question & find its solution
Question:
Answered & Verified by Expert
Poly dispersity index of a polymer is 1.25 If $\overline{\mathrm{M}}_{\mathrm{n}}$ is 800 , what is its $\overline{\mathrm{M}}_{\mathrm{w}}$ ?
Options:
Solution:
2115 Upvotes
Verified Answer
The correct answer is:
$1000$
$\mathrm{PDI}=\frac{\overline{\mathrm{M}}_{\mathrm{W}}}{\overline{\mathrm{M}}_{\mathrm{n}}}=1.25$ (given)
$\overline{\mathrm{M}}_{\mathrm{n}}=800 \Rightarrow \overline{\mathrm{M}}_{\mathrm{W}}=800 \times 1.25=1000$
$\overline{\mathrm{M}}_{\mathrm{n}}=800 \Rightarrow \overline{\mathrm{M}}_{\mathrm{W}}=800 \times 1.25=1000$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.