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Progressive waves are represented by the equation
$\begin{aligned} & y_1=a \sin (\omega t-x) \\ \text { and } \quad & y_2=b \cos (\omega t-x)\end{aligned}$
The phase difference between waves is
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$\begin{aligned} & y_1=a \sin (\omega t-x) \\ \text { and } \quad & y_2=b \cos (\omega t-x)\end{aligned}$
The phase difference between waves is
Solution:
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Verified Answer
The correct answer is:
$90^{\circ}$
As it is clear that the phase difference between $\cos \theta$ and $\sin \theta$ representing two simple harmonic motion is $90^{\circ}$.
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