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$\Delta_{r} G^{\circ}$ for the conversion of $\mathrm{O}_{2}$ to ozone, $\frac{3}{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{O}_{3}(g)$ at $298 \mathrm{~K}$ is $\left(K_{p}\right.$ for this conversion is $1 \times 10^{-29}$ )
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Verified Answer
The correct answer is:
$165.4 \mathrm{~kJ} \mathrm{~mol}^{-1}$
$\Delta_{r} G^{\circ}=-2.303 R T \log K_{p}$
$$
\begin{aligned}
&=-2.303 \times 8.314 \times 298 \times \log \left(1 \times 10^{-29}\right) \\
&=165469.6 \mathrm{~J} \mathrm{~mol}^{-1}=165.47 \mathrm{~kJ} \mathrm{~mol}^{-1}
\end{aligned}
$$
$$
\begin{aligned}
&=-2.303 \times 8.314 \times 298 \times \log \left(1 \times 10^{-29}\right) \\
&=165469.6 \mathrm{~J} \mathrm{~mol}^{-1}=165.47 \mathrm{~kJ} \mathrm{~mol}^{-1}
\end{aligned}
$$
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