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$R-\mathrm{NH}-\mathrm{COH} \xrightarrow[\text { Pyridine }]{\mathrm{POCl}_3}$ product
In the given reaction, what will be the product?
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In the given reaction, what will be the product?
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The correct answer is:
$R-\stackrel{+}{\mathrm{N}} \equiv \mathrm{C}^{-}$
$R-\mathrm{NH}-\mathrm{COH} \xrightarrow[\text { Pyridine }]{\mathrm{POCl}_3} R-\mathrm{N}^{+} \equiv \mathrm{C}^{-}$
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