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Question: Answered & Verified by Expert
Reaction of a carbonyl compound with dilute NaOH gives 4-methylpent-3-en-2-one. The carbonyl compound is:
ChemistryAldehydes and KetonesNEET
Options:
  • A Acetaldehyde
  • B Acetone
  • C Formaldehyde
  • D Propanal
Solution:
1491 Upvotes Verified Answer
The correct answer is: Acetone

The structure of the final product is

The compound is an α,β-unsaturated ketone. Such type of products is formed by the aldol condensation reaction. Among the given reagents, acetone can give the given final product on reactions with dilute NaOH.

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