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Resistance $n$, each of $r$ ohm, when connected in parallel give an equivalent resistance $R \mathrm{~ohm}$. If these resistances were connected in series, the combination would have a resistance in ohms, equal to :
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Verified Answer
The correct answer is:
$n^2 R$
According the question:
$\begin{aligned}
R & =\frac{r}{n} \\
\Rightarrow \quad r & =n R \\
\therefore \quad R \text { series } & =n r=n^2 R
\end{aligned}$
$\begin{aligned}
R & =\frac{r}{n} \\
\Rightarrow \quad r & =n R \\
\therefore \quad R \text { series } & =n r=n^2 R
\end{aligned}$
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