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$\mathrm{S}_{\mathrm{N}} 2$ reaction involving inversion of configuration takes place with an optically active compound $Z$. The compound $Z$ is
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$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}\left(\mathrm{CH}_3\right) \mathrm{X}$
In $\mathrm{S}_{\mathrm{N}} 2$ reaction the nucleophile attacks the electrophilic carbon of the electrophile. The bond between nucleophile and carbon forms at the same time that the bond between carbon and leaving group breaks.
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