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The angles of incidence and emergence of a light ray passing through a prism of angle $A$ are $i$ and e respectively. The total deviation produced by the prism is
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Verified Answer
The correct answer is:
$\mathrm{i}+\mathrm{e}-\mathrm{A}$
Total deviation is given by:
$\begin{aligned} & \delta=\theta_1+\theta_2 \\ & \delta=i-r_1+e-r_2 \\ & =i+e-\left(r_1+r_2\right) . \\ & \delta=i+e-A\end{aligned}$
$\begin{aligned} & \delta=\theta_1+\theta_2 \\ & \delta=i-r_1+e-r_2 \\ & =i+e-\left(r_1+r_2\right) . \\ & \delta=i+e-A\end{aligned}$
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