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The boiling points of $\mathrm{HF}, \mathrm{HCl}, \mathrm{HBr}$ and $\mathrm{HI}$ follow the order
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Verified Answer
The correct answer is:
$\mathrm{HF}>\mathrm{Hl}>\mathrm{HBr}>\mathrm{HCl}$
Due to hydrogen bonding, HF shows highest boiling point.
Thereafter van der Waals' force decide the boiling point.
Larger the size or molecules mass, greater is the van der Waals' forces. Hence, higher is the boiling point.
$\because$ van der Waals' forces is more for HI than HBr, which is in turn is more than HCl.
Hence, correct order is $\mathrm{HF}>\mathrm{Hl}>\mathrm{HBr}>\mathrm{HCl}$
Thereafter van der Waals' force decide the boiling point.
Larger the size or molecules mass, greater is the van der Waals' forces. Hence, higher is the boiling point.
$\because$ van der Waals' forces is more for HI than HBr, which is in turn is more than HCl.
Hence, correct order is $\mathrm{HF}>\mathrm{Hl}>\mathrm{HBr}>\mathrm{HCl}$
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