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The circular scale of a screw gauge has 50 divisions and pitch of $0.5 \mathrm{~mm}$. Find the diameter of sphere. Main scale reading is 2 .
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Verified Answer
The correct answer is:
$1.2$
$1.2$
Least count $\mathrm{LC}=\frac{\text { Pitch }}{\text { Number of divisions on circular scale }}=\frac{0.1}{50}$ $=0.01 \mathrm{~mm}$
Now, diameter of ball $=(2 \times 0.5 \mathrm{~mm})+(25-5)(0.01)=1.2 \mathrm{~mm}$
Now, diameter of ball $=(2 \times 0.5 \mathrm{~mm})+(25-5)(0.01)=1.2 \mathrm{~mm}$
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