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The correct decreasing order of basicity of hydrides of group- 15 elements is
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The correct answer is:
$\mathrm{NH}_3>\mathrm{PH}_3>\mathrm{AsH}_3>\mathrm{SbH}_3$
In general, the basicity of group 15 hydrides
decreases on moving down the group from $\mathrm{NH}_3$ to $\mathrm{SbH}_3$. This is due to the increasing size of the central atom and the decreasing availability of lone pair for donation. Thus, the correct order of basicity of hydrides is
$\mathrm{NH}_3>\mathrm{PH}_3>\mathrm{AsH}_3>\mathrm{SbH}_3$
decreases on moving down the group from $\mathrm{NH}_3$ to $\mathrm{SbH}_3$. This is due to the increasing size of the central atom and the decreasing availability of lone pair for donation. Thus, the correct order of basicity of hydrides is
$\mathrm{NH}_3>\mathrm{PH}_3>\mathrm{AsH}_3>\mathrm{SbH}_3$
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