Degenerate orbitals of ${\left[\text{Cr}{\left({\text{H}}_{\text{2}}\text{O}\right)}_{\text{6}}\right]}^{\text{3+}}$: 

Orbitals having same energy call degenerate orbital, And here water acts as weak ligands which split $\mathrm{d}-$orbital into two parts.

Hence, according to the options given, degenerate orbitals are ${\mathrm{d}}_{\mathrm{x}\mathrm{z}}$ and ${\mathrm{d}}_{\mathrm{y}\mathrm{z}}$.