Search any question & find its solution
Question:
Answered & Verified by Expert
The following reaction is a/an
$\begin{aligned} \mathrm{CH}_3-\mathrm{CH}_2- & \mathrm{CH}_2-\mathrm{Br} \xrightarrow{\mathrm{KOH}} \\ & \mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2+\mathrm{KBr}+\mathrm{H}_2 \mathrm{O}\end{aligned}$
Options:
$\begin{aligned} \mathrm{CH}_3-\mathrm{CH}_2- & \mathrm{CH}_2-\mathrm{Br} \xrightarrow{\mathrm{KOH}} \\ & \mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2+\mathrm{KBr}+\mathrm{H}_2 \mathrm{O}\end{aligned}$
Solution:
2800 Upvotes
Verified Answer
The correct answer is:
elimination reaction
$\begin{aligned} \mathrm{CH}_3-\mathrm{CH}_2- & \mathrm{CH}_2-\mathrm{Br} \xrightarrow{\mathrm{KOH}} \\ & \mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2+\mathrm{KBr}+\mathrm{H}_2 \mathrm{O}\end{aligned}$
In the given reaction alkene is formed from alkane
by elimination of $-\mathrm{H}$ and $-\mathrm{Br}$. So, it is an elimination reaction.
In the given reaction alkene is formed from alkane
by elimination of $-\mathrm{H}$ and $-\mathrm{Br}$. So, it is an elimination reaction.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.