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The formal charges of $\mathrm{N}_{(1)}, \mathrm{N}_{(2)}$ and $\mathrm{O}$ atoms in 
are respectively
Options:
are respectively
Solution:
2029 Upvotes
Verified Answer
The correct answer is:
-1,+1,0
$\begin{aligned} & \text { Formal charge }=\left[\begin{array}{l}\text { Total number of valence } \\ \text { electrons in the free atom }\end{array}\right] \\ & -\left[\begin{array}{l}\text { Total number of } \\ \text { non-bonding (lone } \\ \text { pair)electrons }\end{array}\right]-\frac{1}{2}\left[\begin{array}{l}\text { Total number of } \\ \text { bonding (shared) } \\ \text { electrons }\end{array}\right]\end{aligned}$
In
structure the formal charge on....
the end $\mathrm{N}$ atom marked 1 ,
$\begin{aligned}
& =5-4-\frac{1}{2}(4) \\
& =5-4-2=-1
\end{aligned}$
the central $\mathrm{N}$ atom marked 2 ,
$\begin{aligned}
& =5-0-\frac{1}{2}(8) \\
& =5-4=+1
\end{aligned}$
the end $\mathrm{O}$ atom,
$\begin{aligned}
& =6-4-\frac{1}{2}(4) \\
& =6-6=0
\end{aligned}$
In
structure the formal charge on....
the end $\mathrm{N}$ atom marked 1 ,
$\begin{aligned}
& =5-4-\frac{1}{2}(4) \\
& =5-4-2=-1
\end{aligned}$
the central $\mathrm{N}$ atom marked 2 ,
$\begin{aligned}
& =5-0-\frac{1}{2}(8) \\
& =5-4=+1
\end{aligned}$
the end $\mathrm{O}$ atom,
$\begin{aligned}
& =6-4-\frac{1}{2}(4) \\
& =6-6=0
\end{aligned}$
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