Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The formal potential of $Fe^{3+}/Fe^{2+}$ in a sulphuric acid and phosphoric acid mixture $\left(E^{\circ}=+0.61 \mathrm{V}\right)$ is much lower than the standard potential $\left(E^{\circ}=+0.77 \mathrm{V}\right)$. This is due to
ChemistryElectrochemistryWBJEEWBJEE 2014
Options:
  • A formation of the species $\left[\mathrm{FeHPO}_{4}\right]^{+}$
  • B lowering of potential upon complexation
  • C formation of the species $\left[\mathrm{FeSO}_{4}\right]^{+}$
  • D high acidity of the medium
Solution:
2851 Upvotes Verified Answer
The correct answers are: formation of the species $\left[\mathrm{FeHPO}_{4}\right]^{+}$, lowering of potential upon complexation, high acidity of the medium
Since, $\mathrm{H}_{2} \mathrm{SO}_{4}$ and $\mathrm{H}_{3} \mathrm{PO}_{4}$, both are strong acids so their presence makes the medium more acidic. The $\mathrm{Fe}^{3+}$ ions form complex, IFeHPO $\left._{4}\right]^{+}$ with these acid and hence, the concentration of $\mathrm{Fe}^{3+}$ ion reduces which results in lowering in the formal reduction potential.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.