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The formula of sodium nitroprusside is
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The correct answer is:
$\mathrm{Na}_2\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NO}\right]$
Sodium nitroprusside is known to have the formula $\mathrm{Na}_2\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NO}\right]$. It contains the nitrosyl ($\mathrm{NO}$) ligand, five cyanide ($\mathrm{CN}$) ligands, and an iron ($\mathrm{Fe}$) center. Therefore, the correct formula is $\mathrm{Na}_2\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NO}\right]$.
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