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The fractional change in the volume of a glass slab whe subjected to hydraulic pressure of $14 \mathrm{~atm}$ is (Bulk modulus of glass $=40 \times 10^9 \mathrm{Nm}^{-2}$ )
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The correct answer is:
$3.54 \times 10^{-5}$
Hydraulic pressure exerted on glass slab.
$\mathrm{P}=14 \mathrm{~atm}=14 \times 1.01 \times 10^5 \mathrm{~Pa} \text {. }$
Bulk modules of glass, $\mathrm{B}=40 \times 10^9 \mathrm{Nm}^{-2}$
$\mathrm{B}=\frac{\frac{\mathrm{P}}{\Delta \mathrm{V}}}{\mathrm{V}}$
The fractional change in the volume,
$\begin{aligned}
& \frac{\Delta V}{V}=\frac{P}{B} \\
& =\frac{14 \times 1.01 \times 10^5}{40 \times 10^9}=3.54 \times 10^{-5}
\end{aligned}$
$\mathrm{P}=14 \mathrm{~atm}=14 \times 1.01 \times 10^5 \mathrm{~Pa} \text {. }$
Bulk modules of glass, $\mathrm{B}=40 \times 10^9 \mathrm{Nm}^{-2}$
$\mathrm{B}=\frac{\frac{\mathrm{P}}{\Delta \mathrm{V}}}{\mathrm{V}}$
The fractional change in the volume,
$\begin{aligned}
& \frac{\Delta V}{V}=\frac{P}{B} \\
& =\frac{14 \times 1.01 \times 10^5}{40 \times 10^9}=3.54 \times 10^{-5}
\end{aligned}$
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