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The freezing point of equimolal aqueous solution will be highest for
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$\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6$
Depression in freezing point $\Delta \mathrm{T}_{\mathrm{f}}=\mathrm{iK}_{\mathrm{f}} \mathrm{m}$.
$$
\mathrm{i}=\frac{\text { Total no. of moles of particles after dissociation / association }}{\text { No. of moles of particles before dissociation / association }}
$$
Now, $\mathrm{C}_6 \mathrm{H}_5 \mathrm{NHN}^{+} \mathrm{H}_3 \mathrm{Cl}^{-}, \mathrm{Ba}\left(\mathrm{NO}_3\right)_2, \mathrm{LaCl}_3$ produces 2, 3 and 4 moles of ions after dissociation, respectively. Hence, depression in freezing point will be gradually increasing only $\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6$ does not dissociate in aqueous solution. Therefore, it's solution will have the highest freezing point.
$$
\mathrm{i}=\frac{\text { Total no. of moles of particles after dissociation / association }}{\text { No. of moles of particles before dissociation / association }}
$$
Now, $\mathrm{C}_6 \mathrm{H}_5 \mathrm{NHN}^{+} \mathrm{H}_3 \mathrm{Cl}^{-}, \mathrm{Ba}\left(\mathrm{NO}_3\right)_2, \mathrm{LaCl}_3$ produces 2, 3 and 4 moles of ions after dissociation, respectively. Hence, depression in freezing point will be gradually increasing only $\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6$ does not dissociate in aqueous solution. Therefore, it's solution will have the highest freezing point.
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