The frequencies of two sound sources are 256 H z and 260 H z . At t = 0 , the intensity of sound is maximum. Then the phase difference at the time t = 1 16 s will be

Question

The frequencies of two sound sources are 256 H z and 260 H z . At t = 0 , the intensity of sound is maximum. Then the phase difference at the time t = 1 16 s will be, zero, π, π 2, π 4

MARKS App · Accepted Answer

The time interval between two consecutive beats T = 1 n 1 - n 2 = 1 260 - 256 = 1 4 s So, t = 1 16 = T 4 s By using, time difference = T 2 π × Phase difference ⇒ T 4 = T 2 π × ϕ ⇒ ϕ = π 2

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