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The function $f(x)=a \sin |x|+b e^{| x \mid} \quad$ is differentiable at $x=0$ when
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Verified Answer
The correct answer is:
$a+b=0$
Given, $f(x)=a \sin |x|+b e^{|x|}$
We know that $\sin |x|$ and $e^{|x|}$ is not
differentiable at $x=0$.
Therefore, for $f(x)$ to differentiable at $x=0$, we
must have $a=b=0$.
$\therefore$
$$
a+b=0
$$
We know that $\sin |x|$ and $e^{|x|}$ is not
differentiable at $x=0$.
Therefore, for $f(x)$ to differentiable at $x=0$, we
must have $a=b=0$.
$\therefore$
$$
a+b=0
$$
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