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Question: Answered & Verified by Expert
The function  fx=logx+x2+1 is
MathematicsFunctionsTS EAMCETTS EAMCET 2021 (04 Aug Shift 2)
Options:
  • A An odd function
  • B A periodic function
  • C Neither an even nor an odd function
  • D An even function
Solution:
2830 Upvotes Verified Answer
The correct answer is: An odd function
f-x=log-x+x2+1

=log-x+x2+1x+x2+1×x+x2+1

=log-x2+x2+1x+x2+1

=log1x+x2+1

=-logx+x2+1

=-fx

f-x+fx=0 

Hence, fx is an odd function.

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