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Question: Answered & Verified by Expert
The function fx=tanx+1x, x0,π2 has
MathematicsApplication of DerivativesJEE Main
Options:
  • A one local maximum
  • B one local minimum
  • C one local maximum and one minimum
  • D no local maximum or minimum
Solution:
1538 Upvotes Verified Answer
The correct answer is: one local minimum
dydx=sec2x1x2
=x-cosxx+cosxcos2x.x2

Hence, at α sign of dydx changes from negative to positive       
i.e., y=fx has a local minimum

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