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The function \( f(x)=x^{2}+2 x-5 \) is strictly increasing in the interval
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\( [-1, \infty) \)
Given function, $f(x)=x^{2}+2 x-5$
We know that, for strictly increasing function $f^{\prime}(x)>0$
So, $2 x+2>0$
$\Rightarrow x>-1$
Therefore, function $f(x)=x^{2}+2 x-5$ is strictly increasing in the interval $x \in[-1, \infty)$
We know that, for strictly increasing function $f^{\prime}(x)>0$
So, $2 x+2>0$
$\Rightarrow x>-1$
Therefore, function $f(x)=x^{2}+2 x-5$ is strictly increasing in the interval $x \in[-1, \infty)$
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