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The general solution of $\frac{1-\cos 2 x}{1+\cos 2 x}=3$ is
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The correct answer is:
$x=\mathrm{n} \pi \pm \frac{\pi}{3}, \mathrm{n} \in \mathrm{z}$
$\frac{1-\cos 2 x}{1+\cos 2 x}=3 \Rightarrow \frac{2 \sin ^{2} x}{2 \cos ^{2} x}=3$
$\therefore \tan ^{2} x=3 \Rightarrow \tan ^{2} x=\tan ^{2} \frac{\pi}{3} \Rightarrow x=n \pi \pm \frac{\pi}{3}$
$\therefore \tan ^{2} x=3 \Rightarrow \tan ^{2} x=\tan ^{2} \frac{\pi}{3} \Rightarrow x=n \pi \pm \frac{\pi}{3}$
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