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Question: Answered & Verified by Expert
The given data are for the reaction
2NO(g)+Cl(g)2NOCl(g) at 298 K
 
[Cl2]

[NO]

Initial rate (mol L-1sec-1 )

I

0.05 M

0.05 M

1×10-3

II

0.15 M

0.05 M

3×10-3

III

0.05 M

0.15 M

9×10-3

The rate law of the reaction is
ChemistryChemical KineticsNEET
Options:
  • A rate =k[NO][Cl2]
  • B rate =k[Cl2][NO]2
  • C rate =k[Cl2]2[NO]
  • D rate =k[Cl2]
Solution:
2130 Upvotes Verified Answer
The correct answer is: rate =k[Cl2][NO]2
1×10-3=k[0.05]α[0.05]β …(i)
3×10-3=k[0.15]α[0.05]β …(ii)
9×10-3=k[0.05]α[0.15]β …(iii)
From (i) and (ii), α=1
and from (i) and (iii), β=2
So rate =k[NO]2[Cl2]1 .

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