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The graph correctly represents the variation of acceleration due to gravity $(g)$ with radial distance from the centre of the earth (radius of the earth $=R_e$ ) is
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The correct answer is:
At depth $d$,
$g^{\prime}=g\left(1-\frac{d}{R_e}\right)=g\left(\frac{R_e-d}{R_e}\right)=\frac{g r}{R_e}$
$\Rightarrow g^{\prime} \propto r($ where, $r=$ distance from centre of earth $)$
At height $h$,
$g^{\prime}=g\left(\frac{R_e^2}{\left(R_e+h\right)^2}\right)=\frac{g R_e^2}{r^2} \Rightarrow g^{\prime} \propto \frac{1}{r^2}$
So, correct graph is
$g^{\prime}=g\left(1-\frac{d}{R_e}\right)=g\left(\frac{R_e-d}{R_e}\right)=\frac{g r}{R_e}$
$\Rightarrow g^{\prime} \propto r($ where, $r=$ distance from centre of earth $)$
At height $h$,
$g^{\prime}=g\left(\frac{R_e^2}{\left(R_e+h\right)^2}\right)=\frac{g R_e^2}{r^2} \Rightarrow g^{\prime} \propto \frac{1}{r^2}$
So, correct graph is
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