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The greatest integer which divides $(p+1)(p+2)(p+3) \ldots(p+q)$ for all
$p \in N$ and fixed $q \in N$ is
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$p \in N$ and fixed $q \in N$ is
Solution:
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Verified Answer
The correct answer is:
$q !$
$(p+1)(p+2)(p+3) \ldots(p+q)$ is the product of $q$ consecutive natural number ( $R$ q e $N$ ) The product of $q$ consecutive natural number is always divisible by $q!$
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