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Question: Answered & Verified by Expert
The half life of a radioactive substance is T. The time taken, for disintegrating 78th part of its original mass will be:
PhysicsNuclear PhysicsJEE MainJEE Main 2023 (10 Apr Shift 2)
Options:
  • A 2T
  • B 3T
  • C T
  • D 8T
Solution:
2952 Upvotes Verified Answer
The correct answer is: 3T

It is given that t12= T.

After disintegration of 78thpart, 18th part is only left.

Using the decay formula,

N=N012tt12

N08=N012tT-ln8=-tTln23ln2=tTln2t=3T

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