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Question: Answered & Verified by Expert
The half-life of a radioactive nuclide is 20 h. It is found that the fraction (1x) of original activity remains after 40 hours? What is the value of x?
PhysicsNuclear PhysicsJEE Main
Solution:
2226 Upvotes Verified Answer
The correct answer is: 4
We have   t t 1 / 2 = 4 hours 20  hours = 2

Thus,         A = A 0 2 t / t 1 / 2 = A 0 2 2 = A 0 4

So, one  fourth of the original activity will remain after 40 hours.

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