The hardness of a water sample containing 1 0 - 3 M M g S O 4 expressed as C a C O 3 equivalents (in ppm) is (molar mass of M g S O 4 is 120.38 g / m o l and molar mass of C a C O 3 is 100.08 g / m o l )

Question

The hardness of a water sample containing 1 0 - 3 M M g S O 4 expressed as C a C O 3 equivalents (in ppm) is (molar mass of M g S O 4 is 120.38 g / m o l and molar mass of C a C O 3 is 100.08 g / m o l ), 50, 75, 90, 100

MARKS App · Accepted Answer

Given: 1 0 - 3 M M g S O 4 i.e. 1 0 - 3 mole M g S O 4 present in 1 litre solution n M g S O 4 = n C a C O 3 Mass of C a C O 3 = 1 0 - 3 × 100 ppm (in terms of C a C O 3 ) = m a s s o f C a C O 3 w e i g h t o f so l u t i o n × 1 0 6 ppm (in terms of C a C O 3 ) = 1 0 - 3 × 100 1000 × 1 0 6 = 100 p p m

Search any question & find its solution

Looking for more such questions to practice?