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The hybridisation of \( \mathrm{C} \) in diamond, graphite and ethyne is in the order
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Verified Answer
The correct answer is:
\( s p^{3}, s p^{2}, s p \)
The hybridization of carbon in the following compounds is given in the table below
\begin{array}{|l|l|l|l|}
\hline Compounds & Diamond & Graphite & Ethyne \\
\hline Hybridization of Carbon & \( s p^{3} \) & \( s p^{2} \) & \( \mathrm{sp} \) \\
\hline
\end{array}
\begin{array}{|l|l|l|l|}
\hline Compounds & Diamond & Graphite & Ethyne \\
\hline Hybridization of Carbon & \( s p^{3} \) & \( s p^{2} \) & \( \mathrm{sp} \) \\
\hline
\end{array}
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