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The hybridizations of $\mathrm{Ni}(\mathrm{CO})_{4}$ and $\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}$, respectively, are
ChemistryCoordination CompoundsKVPYKVPY 2011 (SB/SX)
Options:
  • A $\mathrm{sp}^{3}$ and $\mathrm{d}^{3} \mathrm{sp}^{2}$
  • B $\mathrm{dsp}^{2}$ and $\mathrm{d}^{2} \mathrm{sp}^{3}$
  • C $\mathrm{sp}^{3}$ and $\mathrm{d}^{2} \mathrm{sp}^{3}$
  • D $\mathrm{dsp}^{2}$ and $\mathrm{sp}^{3} \mathrm{~d}^{2}$
Solution:
2250 Upvotes Verified Answer
The correct answer is: $\mathrm{sp}^{3}$ and $\mathrm{d}^{2} \mathrm{sp}^{3}$
$\mathrm{Ni}(\mathrm{CO})_{4}$
$\mathrm{Ni}^{0}=3 \mathrm{~d}^{8} 4 \mathrm{~s}^{2}$
By effect of S.F.L. $\mathrm{CO}$.
$\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{+2} \quad \mathrm{Cr}^{+2}=3 \mathrm{~d}^{4} 4 \mathrm{~s}^{0} 4 \mathrm{p}^{0}$

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