The inactivation of a viral preparation in a chemical bath is found to be a first order reaction. The rate constant for the viral inactivation if in the beginning 1.5 % of the virus is inactivated per minute is ( Given : ln 100 98.5 = 0.01511 )

Question

The inactivation of a viral preparation in a chemical bath is found to be a first order reaction. The rate constant for the viral inactivation if in the beginning 1.5 % of the virus is inactivated per minute is ( Given : ln 100 98.5 = 0.01511 ), 1.25 × 10 - 4 s e c - 1, 2.5 × 10 - 4 s e c - 1, 5 × 10 - 4 s e c - 1, 2.5 × 10 - 4 m i n - 1

MARKS App · Accepted Answer

The rate constant for the viral inactivation k = 1 60 ln ⁡ 100 100 - 1.5 k = ( 0.015 ) 60 k = 2.5 × 10 - 4 s e c - 1

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