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Question: Answered & Verified by Expert
The increasing order of the atomic radius of $\mathrm{Si}, \mathrm{S}, \mathrm{Na}, \mathrm{Mg}, \mathrm{Al}$ is
ChemistryClassification of Elements and Periodicity in PropertiesTS EAMCETTS EAMCET 2014
Options:
  • A $\mathrm{S} < \mathrm{Si} < \mathrm{Al} < \mathrm{Mg} < \mathrm{Na}$
  • B $\mathrm{Na} < \mathrm{Al} < \mathrm{Mg} < \mathrm{S} < \mathrm{Si}$
  • C $\mathrm{Na} < \mathrm{Mg} < \mathrm{Si} < \mathrm{Al} < \mathrm{S}$
  • D $\mathrm{Na} < \mathrm{Mg} < \mathrm{Al} < \mathrm{Si} < \mathrm{S}$
Solution:
1617 Upvotes Verified Answer
The correct answer is: $\mathrm{S} < \mathrm{Si} < \mathrm{Al} < \mathrm{Mg} < \mathrm{Na}$
As we move from left to right in a period, effective nuclear charge increases. Due to this atomic radius decreases. Thus, correct order of atomic radii of $3^{\text {rd }}$ period elements is
$\mathrm{Na}>\mathrm{Mg}>\mathrm{Al}>\mathrm{Si}>\mathrm{S}$

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