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The instantaneous value of an $\mathrm{AC}$ is given by $I=5 \sin (\omega t+\phi)$ amp. The rms value of current is
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The correct answer is:
$\frac{5}{\sqrt{2}} \mathrm{~A}$
We know that, $I_{\mathrm{rms}}=\frac{I_{0}}{\sqrt{2}}$
In the given equation, peak value of current $\left(I_{0}\right)=5$
$I_{\mathrm{rms}}=\frac{5}{\sqrt{2}} \mathrm{~A}$
In the given equation, peak value of current $\left(I_{0}\right)=5$
$I_{\mathrm{rms}}=\frac{5}{\sqrt{2}} \mathrm{~A}$
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