The integral ∫ 2 4 log x 2 log x 2 + log 6 - x 2 d x is equal to

Question

The integral ∫ 2 4 log x 2 log x 2 + log 6 - x 2 d x is equal to, 6, 2, 4, 1

MARKS App · Accepted Answer

I = ∫ 2 4 log x 2 log x 2 + log 6 - x 2 d x I = ∫ 2 4 log 6 - x 2 log 6 - x 2 + log x 2 d x ∵ ∫ a b f x d x = ∫ a b f a + b - x d x 2 I = ∫ 2 4 log x 2 + log 6 - x 2 log 6 - x 2 + log x 2 d x 2 I = ∫ 2 4 1 dx 2 I = x 2 4 ∴ I = 1

Search any question & find its solution

Looking for more such questions to practice?