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Question: Answered & Verified by Expert
The intercept on the line $y=x$ by the circle $x^2+y^2-2 x=0$ is $A B$. Equation of the circle on $\mathrm{AB}$ as a diameter is
MathematicsCircleJEE MainJEE Main 2004
Options:
  • A
    $x^2+y^2-x-y=0$
  • B
    $x^2+y^2-x+y=0$
  • C
    $\mathrm{x}^2+\mathrm{y}^2+\mathrm{x}+\mathrm{y}=0$
  • D
    $x^2+y^2+x-y=0$
Solution:
2214 Upvotes Verified Answer
The correct answer is:
$x^2+y^2-x-y=0$
Points of intersection of line $y=x$ with $x^2+y^2-2 x=0$ are $(0,0)$ and $(1,1)$ hence equation of circle having end points of diameter $(0,0)$ and $(1,1)$ is $x^2+y^2-x-y=0$

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