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The interior angles of a polygon of $\mathrm{n}$ sides are in AP. The smallest angle is $120^{\circ}$ and the common difference is $5^{\circ}$
What is the largest interior angle of the polygon?
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What is the largest interior angle of the polygon?
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The correct answer is:
$160^{\circ}$ only
For $n=9$ Largest angle $=T_{9}=120+(9-1) 5=160$
For $n=16$
Largest angle $=T_{16}=120+(16-1) 5=195$
(Not possible).
For $n=16$
Largest angle $=T_{16}=120+(16-1) 5=195$
(Not possible).
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