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Question: Answered & Verified by Expert
The intermediate formed during the addition of $\mathrm{HCl}$ to propene in the presence of peroxide is
ChemistryGeneral Organic ChemistryJEE Main
Options:
  • A $\mathrm{CH}_{3} \mathrm{CHCH}_{2} \mathrm{CI}$
  • B $\mathrm{CH}_{2} \mathrm{CHCH}_{3}$
  • C $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2}$
  • D $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{C} \mathrm{H}_{2}$
Solution:
2962 Upvotes Verified Answer
The correct answer is: $\mathrm{CH}_{2} \mathrm{CHCH}_{3}$
The addition of HCl to propene proceeds by ionic mechanism and not by free radical mechanism. Hence it forms intermediate carbonium ion.

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