The inverse point of ( 1 , 3 ) with respect to the circle x 2 + y 2 − 4 x − 6 y + 9 = 0 is

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The inverse point of $(1,3)$ with respect to the circle $x^2+y^2-4 x-6 y+9=0$ is

MathematicsCircleAP EAMCETAP EAMCET 2017 (25 Apr Shift 1)

Options:

A $(2,3)$
B $(2,-3)$
C $(-2,3)$
D $(-2,-3)$

Solution:

1846 Upvotes Verified Answer

The correct answer is: $(-2,3)$

No solution. Refer to answer key.

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