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The ion with smallest radius among the following is
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Verified Answer
The correct answer is:
$\mathrm{Ti}^{4+}$
All the given species have the elements belonging to the same period and ionic radii decrease in a period from left to right. $\mathrm{Ti}^{4+}$ lies to the right of the other species and would be even more small due to a greater positive charge.
Thus, order of radii would be :-
$$`
\mathrm{K}^{+}>\mathrm{Ca}^{2+}>\mathrm{Sc}^{3+}>\mathrm{Ti}^{4+}
$$
Thus, order of radii would be :-
$$`
\mathrm{K}^{+}>\mathrm{Ca}^{2+}>\mathrm{Sc}^{3+}>\mathrm{Ti}^{4+}
$$
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