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The ionisation energy of an electron in the ground state of helium atom is $24.6 \mathrm{eV}$. The energy required to remove both the electron is
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$79 \mathrm{eV}$
Ionisation energy in ground state $=24.6 \mathrm{eV}$
Energy required to remove $2^{n}$ electron from $\mathrm{He}^{2+}$
Ionisation energy in ground state $=24.6 \mathrm{eV}$
Energy required to remove $2^{n}$ electron from $\mathrm{He}^{2+}$
$=Z^{2}(13.6) \mathrm{eV}=(2)^{2}(13.6)=54.4 \mathrm{eV}$
$=Z^{2}(13.6) \mathrm{eV}=(2)^{2}(13.6)=54.4 \mathrm{eV}$
So, total energy required $=24.6+54.4=79 \mathrm{eV}$
Energy required to remove $2^{n}$ electron from $\mathrm{He}^{2+}$
Ionisation energy in ground state $=24.6 \mathrm{eV}$
Energy required to remove $2^{n}$ electron from $\mathrm{He}^{2+}$
$=Z^{2}(13.6) \mathrm{eV}=(2)^{2}(13.6)=54.4 \mathrm{eV}$
$=Z^{2}(13.6) \mathrm{eV}=(2)^{2}(13.6)=54.4 \mathrm{eV}$
So, total energy required $=24.6+54.4=79 \mathrm{eV}$
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